AbcCabBca
@YuPanPan
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Taiwan
AbcCabBca
4 months ago @Edit 4 months ago
AbcCabBca
4 months ago @Edit 4 months ago
automation:
ACCC(n0, n-1, n2 at the same time) progress:half
dynamic stability (find cct: several trails and outputs) done

https://images.plurk.com/4ezaAKOY2fHin7TKmtAa6R.jpg
https://images.plurk.com/5xDHsGxzbJhtpgsjACQCok.png

definition: _i , _f , _s
https://images.plurk.com/3w2YGnV4PiK3x7Z9bx28Ki.jpg
https://images.plurk.com/2Jwvv4aw9XOGUTrRGA1RN6.jpg
AbcCabBca
4 months ago @Edit 4 months ago
https://images.plurk.com/1pHWQTRO81zPJ13TBktNy5.jpg

unsolved: multi-level ACCC
AbcCabBca
4 months ago @Edit 4 months ago
tr 2nd winding, inducted like a source = "-"d(phi)/dt
lenz's law, 2nd winding = emf, voltage supply (drive current)
→ current direction(physical)then voltage polarity(equivalent model)

phasors' relationship: from i-v of C, L
AbcCabBca
4 months ago @Edit 4 months ago
base case:
潮流分析後存在不合V=0.95-1.03pu之bus
(電抗器、三次側、停用機組)

潮流分析結果之合理性判斷:
1) 收斂
2) 電壓(0.95-1.03pu)(0.9-1.05pu)
3) 發電、負載、損耗間功率平衡(P, Q)
4) 潮流分布、線路使用率
5) 穩定度、敏感度
6) 專家經驗:符合規劃目標、實際數據
AbcCabBca
4 months ago @Edit 4 months ago
[0] 假設: 單一事故發生在單一bus(CB啟斷隔絕)

[2] 單線圖:某一bus故障(非/對稱)
→ 3等效序域(+-0)網路
→由事故bus看出,得各序域(+-0)網路等效Z
→Z(+-0)代入相應非對稱故障If之等效模型
→計算得該bus之If

[1] (abc)相域非對稱故障網路 + 對稱分量分解
→ 各類If相應模型

[3] 區分:單線圖、三相圖(相域、序域、for If等效模型)
AbcCabBca
4 months ago
一個原子,一段DNA,一場生命
什麼堆積了人生?人生又該堆積什麼?
AbcCabBca
4 months ago @Edit 4 months ago
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作者善心大神免費分享,已買其中3本支持
AbcCabBca
4 months ago @Edit 4 months ago
symmetrical component method
y = A x, det(A)≠0
for any y, x=inv(A)*y exists
for specific A,
symmetrical component x=inv(A)*y exists

##########
1 unbalanced sys = sum of 3 balanced sys(+,-,0)
balanced sys: phase a(+-0) ≈ b(+-0) ≈ c(+-0)
only calculate phase a(+-0)

##########
synchronous generator is designed for + sequence; emf only exists in + sequence
AbcCabBca
4 months ago @Edit 4 months ago
https://images.plurk.com/3zELEbmBwtYVMIBcv6RX4a.jpg